Finite Math Examples

$- \frac{1}{3} x + 6 = - \frac{4}{3} x + 18$

Step 1

Combine $x$ and $\frac{1}{3}$ .

$- \frac{x}{3} + 6 = - \frac{4}{3} x + 18$

Step 2

Simplify each term.

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Step 2.1

Combine $x$ and $\frac{4}{3}$ .

$- \frac{x}{3} + 6 = - \frac{x \cdot 4}{3} + 18$

Step 2.2

Move $4$ to the left of $x$ .

$- \frac{x}{3} + 6 = - \frac{4 x}{3} + 18$

Step 3

Move all terms containing $x$ to the left side of the equation.

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Step 3.1

Add $\frac{4 x}{3}$ to both sides of the equation.

$- \frac{x}{3} + 6 + \frac{4 x}{3} = 18$

Step 3.2

Combine the numerators over the common denominator.

$6 + \frac{- x + 4 x}{3} = 18$

Step 3.3

Add $- x$ and $4 x$ .

$6 + \frac{3 x}{3} = 18$

Step 3.4

Cancel the common factor of $3$ .

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Step 3.4.1

Cancel the common factor.

$6 + \frac{3 x}{3} = 18$

Step 3.4.2

Divide $x$ by $1$ .

$6 + x = 18$

Step 4

Move all terms not containing $x$ to the right side of the equation.

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Step 4.1

Subtract $6$ from both sides of the equation.

$x = 18 - 6$

Step 4.2

Subtract $6$ from $18$ .

$x = 12$